Shear force diagrames :- Theses are the diagrams those shows the value of shear force at various sections of the members.
Bending moment diagrams :- These are the diagrams those shows the value of the bending moment at various sections of the members.
(A). CANTILEVER BEAMS :- These beams are fixed from one Ends.
(1). Cantilever beams carry W concentrated load of length l.
Considering any section X from distance x from end B.
So S.F. at X=S=+W
B.M. at X=M= -Wx
at x=0 then M=0
if x=l then M= -Wl
(2). Cantilever beam of length l having uniformaly distributed load w
S.F and B.M at any section X will be
S= wx and M= -(wx^2)/2
if x=l Then
M= -(wl^2)/2
(3). cantilever beam of length l carry uniformly distributed load w per unit length runs in whole length and have concentrated load W at free end.
S= wx+W
M= -{(wx^2)/2 +Wx}
if x= l then
S= (wl+W)
M= -{(wl^2)/2 +Wl}
(4). Cantilever beam of length l ccarry UDL w per unit length for a distance 'a' from the free end
Here, At x=0 S= 0 and M= 0
Now section between A and D distance x from end B
S = +wa
M= -wa{x-(a/2)}
At x=a
M= -wa{l -(a/2)}
(B). SIMPLY SUPPORTED BEAMS :-
(1). SSB have concentrated load W at mid having span length l
S.F. at C point
S = -W/2
BM = M= Wl/4
hence BM increase uniformaly
from zero at A to Wl/4 at C then decrease to zero at B.
(2). SSB have eccentric concentrated load on the span.
assume AD=a and DB=b
Va and Vb are vertical reaction at the ends.
Vb = Wa/l and Va = Wb/l
So, shear force between A and D S = Va = +Wb/l
shear force between D nad B S = Vb = -Wa/l
Bending moment at section between A and D at distance x from A.
M= + (Wb/l)x at x=0 M= 0
if x= a M= Wab/l
(3). SSB carry UDL w per unit length over whole span.
At x=0 S = wl/2 and M=0
At x =l S= -(wl/2) and M = 0
At l/2 S = 0 and M = + (wl^2)/8
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